SCH 3U/4C - Neutralization Reaction

Neutralization of an Acid & a Base

Mixing together equal amounts (numbers of moles) of an acid and a base results in neutralization reaction (another double replacement reaction).  The mixing of an acid and a base always produces a salt (ionic compound) and water.  The products, the salt and water, are both neutral and the resulting solution has a pH of 7.

Acid  +  Base  →  Salt (Ionic Compound)  +  Water

HCl(aq)  +  KOH(aq)  →  KCl(aq)  +  HOH(l)

2HNO₃(aq)  +  Ca(OH)₂(aq)  →  Ca(NO₃)₂(aq)  +  2HOH(l)

• note: it doesn't matter whether you write the formula for water as HOH or H₂O.

 

 

Now, go on to to the Acid-Base Titration lesson.

Homework:

Complete the word equation and write a balanced equation for the reaction of the two given aqueous solutions in each case.  Be sure to include state symbols (hint: use your solubility rules when appropriate).

(a) sulfuric acid + sodium hydroxide →

(b) hydrobromic acid + magnesium hydroxide →

Answers:

sulfuric acid + sodium hydroxide → sodium sulfate + water

H₂SO₄(aq)  +  2NaOH  →  Na₂SO₄(aq) +  2H₂O(l)

 

hydrobromic acid + magnesium hydroxide → magnesium bromide + water

2HBr(aq)  +  Mg(OH)₂  →  MgBr₂(aq)  +  2H₂O(l)