Tuesday, March 10, 2020

SCH 3U/4C - Predicting Products for Synthesis & Decomposition Reactions

As we remember how to predict products for the different types of reactions, we will typically be given the start of a word equation.  We will then be responsible for finishing the word equation and providing a balanced equation.

 

Predicting Products – Synthesis Reactions

Remember that synthesis reactions involve the reaction of two (or more) substances to produce one product.  Typically, this means that two elements will combine to form one compound.

  • Oxidation: Metal or Non-metal + O2    Oxide

calcium  +  oxygen    calcium oxide

    2Ca    +     O2             2CaO

*When finishing the word equation, think about the compound that would contain the combination of elements from the reactant side.

*When creating the balanced equation, be sure to think about whether the elemental reactants are regular monoatomics or if they are “special dudes" (H2, N2, O2, F2, Cl2, Br2, I2, P4, S8).  Also, be sure to use the valences of the elements to create the formula of the product.


  • Metal + Non-metal    Binary Compound

sodium  +  chlorine    sodium chloride

   2Na     +     Cl2               2NaCl

 

  • Metal Oxide + H2O    Base

magnesium oxide  +  water   →  magnesium hydroxide

             MgO          +  H2O             Mg(OH)2 

*Notice that the product contains all of the atoms that are found in the reactants (Mg, O, H).  Since we need to create a base (which must contain the hydroxide ion), it makes the most sense to combine the elements into magnesium hydroxide.


  •  Non-metal Oxide + H2O    Acid

carbon dioxide  +  water  →  carbonic acid

          CO2         +  H2O        H2CO3(aq)

* Notice that the product contains all of the atoms that are found in the reactants (H, C, O).  Since we need to create an acid (which must start with a hydrogen ion), it makes the most sense to think about which polyatomic ion contains C & O.  The first ion that comes to mind is carbonate.  So, by combining H (valence +1) and carbonate (valence -2), we arrive at carbonic acid.  We could have used percarbonate, carbonite or hypocarbonite instead of carbonate, but that would complicate the balancing.  Make your life easy and always choose the polyatomic ion that creates the acid in an easy to balance equation.

 

*Note that for multivalent elements, more than one product is possible.

carbon  +  oxygen    carbon (IV) oxide     

     C      +     O2                 CO2

carbon  +  oxygen    carbon (II) oxide

    2C     +     O2                 2CO     

                               

Combustion Reactions

Complete combustion is the reaction of a hydrocarbon with oxygen to form carbon dioxide and water.  Incomplete combustion results in a different mixture of products.  We will almost always be using complete combustion in our work (and hence, I will just say "combustion" - if I want you to use incomplete combustion, I will say "incomplete combustion").

  • Complete Combustion of a Hydrocarbon 

methane  +  oxygen    carbon dioxide  +  water

    CH4     +     2O2               CO2          +  2H2O

  •  Incomplete Combustion 

*occurs when the concentration of O2 is low

hydrocarbon   +  O2    C  +  CO  +  H2O  

 

Predicting Products – Decomposition Reactions

Remember that decomposition reactions are the opposite of synthesis reactions.  Thus, one reactant will break down into simpler components (usually just the elements found in the compound).  Use the valences of the elements to predict the reactants.  Also, be sure to think about whether the products are "special dudes" (H2, N2, O2, F2, Cl2, Br2, I2, P4, S8). 

  • Binary Compound   Element  +  Element

hydrogen bromide    hydrogen  +  bromine

            2HBr                  H2       +      Br2

 

Homework:


Finish the word equation and provide a balanced equation for each:

(a) sulfur + oxygen

(b) copper + chlorine

(c) sodium oxide + water

(d) nickel + fluorine

(e) carbon dioxide + water

(f) lithium oxide + water

(g) sulfur dioxide + water

(h) methane (CH4) + oxygen

(i) octane (C8H18) + oxygen

 

Answers: